4=0.01v^2

Solution for 4=0.01v^2 equation:

4=0.01v^2

We move all terms to the left:

4-(0.01v^2)=0

We get rid of parentheses

-0.01v^2+4=0

a = -0.01; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-0.01)·4
Δ = 0.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.16}}{2*-0.01}=\frac{0-\sqrt{0.16}}{-0.02}
=-\frac{\sqrt{}}{-0.02}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.16}}{2*-0.01}=\frac{0+\sqrt{0.16}}{-0.02}
=\frac{\sqrt{}}{-0.02}
$